Which of the following is correct for a two-d | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In $2D$ square packing,the coordination number is $4$ and the packing fraction is $\frac{\pi}{4} \approx 0.785$. In $2D$ hexagonal packing,the coo

Vedclass · Accepted Answer

In hexagonal close packing,each atom is surrounded by six trigonal planar voids.

Vedclass · Answer

(D) In $2D$ square packing,the coordination number is $4$ and the packing fraction is $\frac{\pi}{4} \approx 0.785$. In $2D$ hexagonal packing,the coordination number is $6$ and the packing fraction is $\frac{\pi}{2\sqrt{3}} \approx 0.906$. Since the packing fraction of hexagonal packing $(0.906)$ is higher than square packing $(0.785)$,the void fraction $(1 - 	ext{packing fraction})$ of hexagonal packing is lower than that of square packing. In $2D$ hexagonal close packing,each atom is in contact with $6$ other atoms,creating $6$ trigonal planar voids around it.

Which of the following is correct for a two-dimensional closed-packed crystal?

Similar Questions

If a compound (oxide) has an $hcp$ arrangement and the cations $M$ occupy two-thirds of the octahedral voids,the formula of the compound is:

What is the number of octahedral and tetrahedral voids present respectively in $0.25 \ mol$ of a substance having $hcp$ structure?

In a crystalline solid,anion $B$ are arranged in $ccp$ lattice and cation $A$ occupy $50\%$ of the octahedral voids and $50\%$ of tetrahedral voids. What will be the formula of the crystalline solid?

Which of the following metals has an $hcp$ crystal structure?

Atoms of element $A$ occupy $\frac{1}{3}$ of the octahedral voids,while atoms of element $B$ form an $hcp$ structure. Determine the formula of the compound formed by $A$ and $B$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module